integral 1 per 2 x akar x dx

Hopefullythis helps! Answer link. The integral is 2/15 (x^3 + 1)^ (5/2) - 2/9 (x^3 + 1)^ (3/2) + C Let u = x^3 + 1. Then du = 3x^2dx -> dx = (du)/ (3x^2). Let I be the integral. I= intx^5sqrt (u) * (du)/ (3x^2) I = 1/3intx^3sqrt (u)du I = 1/3int (u - 1)sqrt (u)du I = 1/3int (u - 1)u^ (1/2)du I = 1/3int u^ (3/2) - u^ (1/2)du I = 1/3intu^ (3/2 integral(x^4-x akar(x))/akar(x^3) dx= Integral Tak Tentu sebagai Anti Turunan; Integral; KALKULUS; Matematika. Share. Rekomendasi video solusi lainnya 02:52. Hasil dari integral (x-1)/(x^2-2x+4)^1/2 dx adalah Hasil dari integral (x-1)/(x^2-2x+4)^1/2 dx adalah 03:52. Jika turunan pertama dari f(x) adalah f'(x)=6x^2-2x+1 dan Itis helpful to draw a right triangle with angle tan−1(x +1), adjacent side 1, opposite side x + 1 and hypotenuse x2 +2x +2. And remember that cos2w = 2cos2w −1, sin2w = 2sinwcosw. If the initial substitution is hard to spot, substitute u = x + 1 first in order to get rid of the 2x, giving ∫ du (u2 + 1)2 then further substitute u = tanw Given ∫ 1 + x 1 − x dx. We know that 1 + x 1 − x = 2 − (1 − x) 1 − x. = 2 1 − x −1. Now, we got ∫( 2 1 − x −1) dx. Using the sum rule, ∫(f (a) +f (b)) dx = ∫f (a) +∫f (b) So, we have. = ∫ 2 1 − x dx − ∫1 dx. Now, we use u-substitution to compute ∫ 2 1 −x dx. Let u = 1 − x, then du dx = − 1,dx = du H5 Ffcredit.

integral 1 per 2 x akar x dx